- How many grams are in 0.2 moles of KCl (Molar mass = 74.5 g/mol)?
a) 14.9 g
b) 15 g
c) 20 g
d) 25 g
Answer: a) 14.9 g
Explanation: 0.2 moles × 74.5 g/mol = 14.9 g.
- The number of moles in 64 g of O₂ is:
a) 1 mole
b) 2 moles
c) 3 moles
d) 4 moles
Answer: b) 2 moles
Explanation: 64 g ÷ 32 g/mol = 2 moles.
- In the reaction 4Fe + 3O₂ → 2Fe₂O₃, how many moles of Fe are required to react with 1 mole of O₂?
a) 4/3 moles
b) 2 moles
c) 1.5 moles
d) 3 moles
Answer: a) 4/3 moles
Explanation: The mole ratio indicates that 4 moles of Fe react with 3 moles of O₂, so 1 mole of O₂ requires 4/3 moles of Fe.
- What is the molar mass of ammonium nitrate (NH₄NO₃)?
a) 80 g/mol
b) 90 g/mol
c) 100 g/mol
d) 150 g/mol
Answer: b) 90 g/mol
Explanation: Molar mass is calculated as (14 + 4) + (14 + 3 × 16) = 90 g/mol.
- How many molecules are in 4 moles of glucose (C₆H₁₂O₆)?
a) 2.41 × 10²³
b) 2.41 × 10²⁴
c) 1.81 × 10²⁴
d) 3.01 × 10²²
Answer: b) 2.41 × 10²⁴
Explanation: 4 moles × 6.022 × 10²³ molecules/mole = 2.41 × 10²⁴ molecules.
- The molar mass of phosphoric acid (H₃PO₄) is:
a) 95 g/mol
b) 98 g/mol
c) 100 g/mol
d) 105 g/mol
Answer: b) 98 g/mol
Explanation: Molar mass is calculated as (3 × 1) + (31) + (4 × 16) = 98 g/mol.
- In a chemical reaction, if you have 1 mole of A and it reacts with 3 moles of B, what is the total number of moles of products formed if 1 mole of A is completely consumed?
a) 1 mole
b) 2 moles
c) 4 moles
d) 3 moles
Answer: c) 4 moles
Explanation: If 1 mole of A and 3 moles of B react, the total moles of products will be the sum of moles of A and B consumed.
- What is the volume occupied by 3 moles of an ideal gas at STP?
a) 33.6 L
b) 67.2 L
c) 22.4 L
d) 60 L
Answer: b) 67.2 L
Explanation: 3 moles × 22.4 L/mole = 67.2 L.
- The mass of 2.5 moles of CaCO₃ (Molar mass = 100 g/mol) is:
a) 250 g
b) 200 g
c) 150 g
d) 125 g
Answer: a) 250 g
Explanation: 2.5 moles × 100 g/mol = 250 g.
- How many moles of K are in 100 g of KCl (Molar mass = 74.5 g/mol)?
a) 1.35 moles
b) 2.35 moles
c) 1.5 moles
d) 0.5 moles
Answer: a) 1.35 moles
Explanation: 100 g ÷ 74.5 g/mol = 1.35 moles of KCl, which contains 1.35 moles of K.
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